xp and new motherboard?

Discussion in 'General Hardware' started by da rock, Apr 20, 2002.

  1. da rock

    da rock Guest

    i've got to replace the motherboard on my wifes pc,not upgrading
    any components just replacing the mobo.will i be able to use xp
    thats already installed on the harddrive or am i gonna end up
    having to buy another copy?:cool:
     
  2. MiseryQ

    MiseryQ Guest

    If you bought a copy for her computer already then you DON't need to buy another copy just because yuor changing parts... You might have to call MS for activation however...
     
  3. The Lexx

    The Lexx Guest

    Not might have to call MS you will have to call MS, I had this porblem when I replaced my MB, it only took 5mins
     
  4. da rock

    da rock Guest

    ok,i can deal with that! thanks guys!;)
     
  5. bmxjt

    bmxjt Guest

    not necessarily true.. I just had my mobo changed 2 days ago and I didnt have to reinstall or call for activation. Of cours eit wouldnt boot right up, but I booted off of the cd and repaired. Then after about 4 tries at booting, it installed itself and kept all my old info.
     
  6. Sage

    Sage Guest

    no need to call MS

    Copy WPA.DBL from the windows>system32 folder to a floppy, then once you have installed the new board and are up and running just replace this file - no reactivation needed.
     
  7. The Lexx

    The Lexx Guest

    This may not work try with caution
     
  8. MiseryQ

    MiseryQ Guest

    By changing your mother board and NOT reinstalling you keep all of your old board driver... A situation I don't like...

    I thought the WPA.DBL trick only worked when the hardware was identical...
     
  9. bmxjt

    bmxjt Guest

    well, so far my system seems to be running fine
     
  10. da rock

    da rock Guest

    i just finished putting everything back togather,spent maybe 5 min
    reactivating xp and i'm pleased to say that all systems are go!
    also solved my problem w printer sharing on my network.

    once again,thanks to all;)