[PHP] 'if' question

Glaanieboy

OSNN Veteran Addict
Joined
Mar 6, 2002
Messages
2,626
#1
I currently have a if statement like this:
Code:
if ($host2 == "co" || $host2 == "org" || $host2 == "net" || $host2 == "ac"){
As you can see, $host2 can be different values, if it is one of those values, then it should do something. It all works perfectly, but I have to add more '$host2 == "value" ' thingies there and I am afarid the list is going to be too long. I know that I can put all those values in a array, but how can I check those values with an 'if'?
 

Khayman

I'm sorry Hal...
Political User
Joined
Jan 6, 2002
Messages
5,518
#2
You could do a switch statment

Code:
switch($host2)
{
case "co":
   //do blah
   break;
case "org":
 //more blah
   break;
case "net":
   //blah balh
   break;
}
can keep doing that forever
 

Khayman

I'm sorry Hal...
Political User
Joined
Jan 6, 2002
Messages
5,518
#3
Or using an array

Code:
$valuestomatchon = array('co','org,'net','ac');

$count = array_count_values(($valuestomatchon);
for ($i = 0; $i < $count; $i++) 
{
 if ($host2 == valuestomatchon[count])
 //do somthing
}
 

Glaanieboy

OSNN Veteran Addict
Joined
Mar 6, 2002
Messages
2,626
#4
Let me give the part of the script I am talking about:
Code:
if ($host2 == "co" || $host2 == "org" || $host2 == "net" || $host2 == "ac"){
 $host = "$host1.$host2.$host3";
}else{
 $host = "$host2.$host3";
}
As you can see, when it has found of those values, it makes a different $host than when those values aren't found. It doesn't matter if it's "co" or "org", it does the same. Only until $host2 doesn't contain one of those values, the other part is being executed.
I hope I am making sense here.

edit: Yes, that array example you gave is good. I will use that.
 

Khayman

I'm sorry Hal...
Political User
Joined
Jan 6, 2002
Messages
5,518
#5
i found a better way
Code:
$valuestomatchon = array('co','org,'net','ac');

if (in_array($host2, $valuestomatchon)) 
{
echo "Found it"
}
 

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