# little c++ question

#### mike09

##### Moderator
im new to programming but how can i prove that am integer is even. cause i need ot make a program the says if the number that was inputed is either even or odd. thanks in advance.

#### NetRyder

##### Tech Junkie
Use the modulus (%) operator. If the variable is "int foo" and you want to check that foo is even, here's the snippet of code:

Code:
``````if(foo%2 == 0)
cout << "The number is even \n";
else
cout << "The number is odd \n";``````

#### NetRyder

##### Tech Junkie
Just thought I'd mention what the modulus operator does, in case you don't already know.

When you divide two integers, the modulus is the remainder that you get. So for example, if you divide any even number by 2, you should get a remainder of 0. That's why you check to see if foo%2 == 0. If the value of foo was odd, the remainder would be 1.

Hope that helps

#### mike09

##### Moderator
so what would the header file be...
modulus.h
im not sure cause i havent learned it yet.

#### NetRyder

##### Tech Junkie
No, you don't need any special headers to be included. It's a standard math operator just like +, -, * and /
Just include iostream.h for cout and cin.

#### NetRyder

##### Tech Junkie
Code:
``````#include <iostream.h>

main() {
int foo;
cout << "Enter a number: ";
cin >> foo;
if(foo%2 == 0)
cout << "The number is even \n";
else
cout << "The number is odd \n";

return 0;
}``````
That's it

#### Geffy

##### Moderator
I think stdio.h or if not that one then certainly math.h should have it

#### mike09

##### Moderator
thank you all very much for the help.

#### X-Istence

##### *
Political User
Originally posted by Geffy
I think stdio.h or if not that one then certainly math.h should have it

Nope, both are not needed.

#### NetRyder

##### Tech Junkie
That's right...the math operators are just there for you to use

#### X-Istence

##### *
Political User
Originally posted by NetRyder
That's right...the math operators are just there for you to use
Only the basic ones.

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