the simplest servlet...and it doesn't work.help need!!pls

[Biggie_mac]

I have a very simple servlet to run....and it doesn't work..I dwl Tomcat 5.0.28, installed it to C:\Tomcat 5....started the procces, typed localhost:8080 in the browser...everything worked out. I even tried some of thei examples and they worked. Now I want to run this very simple servlet:

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;

public class SimpleCounter extends HttpServlet {

int count = 0;

public void doGet(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
res.setContentType("text/plain");
PrintWriter out = res.getWriter();
count++;
out.println("Since loading, this servlet has been accessed " +
count + " times.");
}
}


I saved the file as SimpleCounter.java, copy it to ROOT/Web-inf/classes/ and typed localhost:8080/servlet/SimpleCounter.
As I read on tutorials and books this is the simplest way to run a servlet. But it doesn't work for me!! I get this message:

HTTP Status 404 - /servlet/SimpleCounter
type Status report
message /servlet/SimpleCounter
description The requested resource (/servlet/SimpleCounter) is not available.
Apache Tomcat/5.0.28


What am I doing wrong? I'm new with servlets so ....

10x very much!!

 

[Geffy]

its been a while since I last did Servlets but I think you need to compile the SimpleCounter.java into SimpleCounter.class

do this

javac SimpleCounter.java

and you should end up with a compiled version. Then it should work.

From what I remember JSP files are compiled by tomcat the first time they are run and from there they are used in the byte form. I think Servlets you have to do though.